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Partial fractions 1/(x^3+2x^2-x-2) Step-by-step solution STEP 2 Factor the denominator into linear and irreducible quadratic terms: 1 (x − 1) (x + 1) (x + 2) STEP 3 Then the partial fraction expansion is of the form: θ₁ x − 1 + θ₂ x + 1 + θ₃ x + 2 Answer 1 2 (x + 1) + 1 3 (x + 2) + 1 6 (x − 1)

Step-by-Step Solutions Features

Step-by-Step Solutions

Not just answers—step-by-step solutions buttons expand answers and explain how that answer was found.

Wolfram|Alpha Step-by-step solution Limit: Limit Step-by-step solution Decimal form STEP 1

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Break steps down even further with intermediate steps. These optional additional explanations for individual pieces of step-by-step solutions help guide you.

STEP 3 Hide intermediate steps INTERMEDIATE STEPS:

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Wolfram|Alpha Step-by-step solution Exact result: Hide hints Use long division Reduce to lowest terms STEP 1 STEP 2 Hint: Look for a multiple of 67 that is close to but not greater than 529 (the first 3 digits of the dividend).

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Your own tutor—hints are also frequently provided to not just provide answers, but also to guide you towards finding the solution yourself.

Wolfram|Alpha Step-by-step solution Results: Hide hints STEP 1 STEP 2 Hint: Multiply x + 3 and x + 3 together using FOIL.

Examples of Step-by-Step Solutions

Explore some of the content areas covered by step-by-step solutions, including math, chemistry and physics, or view more examples »

Wolfram|Alpha Step-by-step solution Limit: Hide hints STEP 2 Hint: Factor the numerator and denominator. STEP 3 Hint: Cancel terms.
Wolfram|Alpha Step-by-step solution Solutions: Hide hints STEP 2 Hint: Use the double angle identity on sin(2 x). STEP 3 Hint: Use the quadruple angle identity on cos(4 x).
Wolfram|Alpha Step-by-step solution Exact result: Hide hints Use long division STEP 1 STEP 2 Hint: Look for a multiple of 67 that is close to but not greater than 529 (the first 3 digits of the dividend).
Wolfram|Alpha Step-by-step solution Results: Hide hints STEP 1 STEP 2 Hint: The eigenvalues of a matrix M are those numbers λ ∈ C such that M v = λ v for some nonzero vector v.
Wolfram|Alpha Step-by-step solution Results: STEP 2

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